integral from 10 to 20 of 3x^2+6x+300

Lösung

\int_{10}^{20} 3 x^{2} + 6 x + 300 d x

10900

Schritte zur Lösung

\int_{10}^{20} 3 x^{2} + 6 x + 300 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{10}^{20} 3 x^{2} d x + \int_{10}^{20} 6 x d x + \int_{10}^{20} 300 d x

\int_{10}^{20} 3 x^{2} d x = 7000

\int_{10}^{20} 6 x d x = 900

\int_{10}^{20} 300 d x = 3000

= 7000 + 900 + 3000

Vereinfache

= 10900

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