integral from 2 to 1 of 1x^5

Lösung

\int_{2}^{1} 1 x^{5} d x

- \frac{21}{2}

Dezimale

- 10.5

Schritte zur Lösung

\int_{2}^{1} 1 \cdot x^{5} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{2} 1 \cdot x^{5} d x

Vereinfache

= - \int_{1}^{2} x^{5} d x

Wende die Potenzregel an

= - [\frac{x ^{6}}{6}]_{1}^{2}

Berechne die Grenzen:

\frac{21}{2}

= - \frac{21}{2}

\int_{1}^{5} (\frac{1}{2 x - 1}) d x

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\int_{3}^{5} sin (ln (x)) d x

\int_{0}^{\frac{1}{2}} cos (x) d x

\int_{π}^{2 π} \frac{sin ( x )}{x} d x