integral from 0 to 5 of x^2+1

Lösung

\int_{0}^{5} x^{2} + 1 d x

\frac{140}{3}

Dezimale

46.66666 \dots

Schritte zur Lösung

\int_{0}^{5} x^{2} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{5} x^{2} d x + \int_{0}^{5} 1 d x

\int_{0}^{5} x^{2} d x = \frac{125}{3}

\int_{0}^{5} 1 d x = 5

= \frac{125}{3} + 5

Vereinfache

\frac{125}{3} + 5 : \frac{140}{3}

= \frac{140}{3}

\int_{0}^{5} x^{2} + 5 d x

\int_{0}^{3} π y^{\frac{2}{3}} d y

\int_{2 x}^{x^{5}} e^{- t^{2}} d t

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