integral from 0 to 8 of 16x-128

Lösung

\int_{0}^{8} 16 x - 128 d x

- 512

Schritte zur Lösung

\int_{0}^{8} 16 x - 128 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{8} 16 x d x - \int_{0}^{8} 128 d x

\int_{0}^{8} 16 x d x = 512

\int_{0}^{8} 128 d x = 1024

= 512 - 1024

Vereinfache

= - 512

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