integral from 0 to 1-x of x

Lösung

\int_{0}^{1 - x} x d x

\frac{( - x + 1 ) ^{2}}{2}

Schritte zur Lösung

\int_{0}^{1 - x} x d x

Wende die Potenzregel an

= [\frac{x ^{2}}{2}]_{0}^{1 - x}

Berechne die Grenzen:

\frac{1}{2} (- x + 1)^{2}

= \frac{1}{2} (- x + 1)^{2}

Vereinfache

= \frac{( - x + 1 ) ^{2}}{2}

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