integral from 0 to 3 of (e^x+x)

Lösung

\int_{0}^{3} (e^{x} + x) d x

e^{3} + \frac{7}{2}

Dezimale

23.58553 \dots

Schritte zur Lösung

\int_{0}^{3} e^{x} + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} e^{x} d x + \int_{0}^{3} x d x

\int_{0}^{3} e^{x} d x = e^{3} - 1

\int_{0}^{3} x d x = \frac{9}{2}

= e^{3} - 1 + \frac{9}{2}

Ziehe Brüche zusammen

- 1 + \frac{9}{2} : \frac{7}{2}

= e^{3} + \frac{7}{2}

\int_{1}^{2} \frac{3 x ^{2} - 1}{x ^{2}} d x

\int_{0}^{1} 4 x 2 x^{2} + 5 d x

\int_{0}^{1} x e^{x y} d y

\int_{0}^{12} \frac{x}{25 + 2 x} d x

\int_{1}^{x} \frac{sin ( t )}{t} d t