integral from 4.9 to 7.1 of 12x^2-6x+4/x

解

\int_{4.9}^{7.1} 12 x^{2} - 6 x + \frac{4}{x} d x

883.33143 \dots

解答ステップ

\int_{4.9}^{7.1} 12 x^{2} - 6 x + \frac{4}{x} d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4.9}^{7.1} 12 x^{2} d x - \int_{4.9}^{7.1} 6 x d x + \int_{4.9}^{7.1} \frac{4}{x} d x

\int_{4.9}^{7.1} 12 x^{2} d x = 961.048

\int_{4.9}^{7.1} 6 x d x = 79.2

\int_{4.9}^{7.1} \frac{4}{x} d x = 1.48343 \dots

= 961.048 - 79.2 + 1.48343 \dots

簡素化

= 883.33143 \dots