integral from 0 to 4 of (7x+sqrt(x))

Lösung

\int_{0}^{4} (7 x + x) d x

\frac{184}{3}

Dezimale

61.33333 \dots

Schritte zur Lösung

\int_{0}^{4} 7 x + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 7 x d x + \int_{0}^{4} x d x

\int_{0}^{4} 7 x d x = 56

\int_{0}^{4} x d x = \frac{16}{3}

= 56 + \frac{16}{3}

Vereinfache

56 + \frac{16}{3} : \frac{184}{3}

= \frac{184}{3}

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