integral from 1 to 3 of 2x-1

Lösung

\int_{1}^{3} 2 x - 1 d x

6

Schritte zur Lösung

\int_{1}^{3} 2 x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 2 x d x - \int_{1}^{3} 1 d x

\int_{1}^{3} 2 x d x = 8

\int_{1}^{3} 1 d x = 2

= 8 - 2

Vereinfache

= 6

\int_{1}^{2} (x + 2) d x

\int_{0}^{3} ∣ 3 x - 8 ∣ d x

\int_{2 x}^{x^{2}} cos (t) sin (t) d t

\int_{0}^{1 - x} \frac{( 1 - x - y ) ^{2}}{2} d y

\int_{0}^{2} x^{2} + x + 1 d x