What is the integral of xsin(-1x) ?

The integral of xsin(-1x) is xcos(x)-sin(x)+C

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integral of xsin(-1x)

\int x sin (- 1 x) d x

x cos (x) - sin (x) + C

Solution steps

\int x sin (- 1 \cdot x) d x

Simplify

x sin (- 1 \cdot x) : - x sin (x)

= \int - x sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int x sin (x) d x

Apply Integration By Parts

: - x cos (x) - \int - cos (x) d x

= - (- x cos (x) - \int - cos (x) d x)

\int - cos (x) d x = - sin (x)

= - (- x cos (x) - (- sin (x)))

Simplify

= x cos (x) - sin (x)

Add a constant to the solution

= x cos (x) - sin (x) + C

\int e^{- y} d y

F (x) = sin (tan (3 x))

\frac{d}{d x} (ln (3 x + 1))

\frac{d}{d x} (sin^{5} (2 x^{5} - e^{- 2 x}))

y = x^{3} - 3 x^{2} + 1

What is the integral of xsin(-1x) ?
The integral of xsin(-1x) is xcos(x)-sin(x)+C