integral from 0 to 1 of sin(x)cos(x)

Lösung

\int_{0}^{1} sin (x) cos (x) d x

\frac{sin ^{2} ( 1 )}{2}

Dezimale

0.35403 \dots

Schritte zur Lösung

\int_{0}^{1} sin (x) cos (x) d x

Wende U-Substitution an

= \int_{0}^{s i n (1)} u d u

Wende die Potenzregel an

= [\frac{u ^{2}}{2}]_{0}^{s i n (1)}

Berechne die Grenzen:

\frac{sin ^{2} ( 1 )}{2}

= \frac{sin ^{2} ( 1 )}{2}

\int_{1}^{1} 1 + x^{4} d x

\int_{1}^{3} 2 (1 + ln (x)) x^{2 x} d x

\int_{- 3}^{0} 1 d x

\int_{1}^{e^{1}} sin (ln (x)) d x

\int_{4}^{7} \frac{1}{x ^{2}} d x