integral from 0 to pi of cos(2x)sin(5x)

Lösung

\int_{0}^{π} cos (2 x) sin (5 x) d x

\frac{10}{21}

Dezimale

0.47619 \dots

Schritte zur Lösung

\int_{0}^{π} cos (2 x) sin (5 x) d x

Verwende die folgenden Identitäten:

cos (t) sin (s) = \frac{sin ( s + t ) + sin ( s - t )}{2}

= \int_{0}^{π} \frac{sin ( 5 x + 2 x ) + sin ( 5 x - 2 x )}{2} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{π} sin (5 x + 2 x) + sin (5 x - 2 x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int_{0}^{π} sin (5 x + 2 x) d x + \int_{0}^{π} sin (5 x - 2 x) d x)

\int_{0}^{π} sin (5 x + 2 x) d x = \frac{2}{7}

\int_{0}^{π} sin (5 x - 2 x) d x = \frac{2}{3}

= \frac{1}{2} (\frac{2}{7} + \frac{2}{3})

Vereinfache

\frac{1}{2} (\frac{2}{7} + \frac{2}{3}) : \frac{10}{21}

= \frac{10}{21}

\int_{2}^{3} (x^{3} - 3 x^{2} + x - 4) d x

\int_{0}^{4} (10 - t) t d t

\int_{0}^{3} x e^{3 x} d x

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\int_{0}^{1} [2 x] sin (π x) d x