What is the integral from 1 to infinity of 9/(x^4) ?

The integral from 1 to infinity of 9/(x^4) is 3

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integral from 1 to infinity of 9/(x^4)

\int_{1}^{\infty} \frac{9}{x ^{4}} d x

3

Solution steps

\int_{1}^{\infty} \frac{9}{x ^{4}} d x

Compute the indefinite integral:

\int \frac{9}{x ^{4}} d x = - \frac{3}{x ^{3}} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{9}{x ^{4}} d x = 0 - (- 3)

= 0 - (- 3)

Simplify

= 3

\frac{\partial}{\partial x} ((x^{4} - 1) (x^{2} + 1))

\frac{\partial}{\partial y} (y sin (x))

x \to 2 + lim (2^{x} - 4)

x \to 1 + lim (ln^{x} (x))

\int \frac{4 \cdot x + 3}{x ^{2} - 25} d x

What is the integral from 1 to infinity of 9/(x^4) ?
The integral from 1 to infinity of 9/(x^4) is 3