integral from-2 to 0 of 1/(e^{-2x)}

Lösung

\int_{- 2}^{0} \frac{1}{e ^{- 2 x}} d x

\frac{e ^{4} - 1}{2 e ^{4}}

Dezimale

0.49084 \dots

Schritte zur Lösung

\int_{- 2}^{0} \frac{1}{e ^{- 2 x}} d x

Wende Exponentenregel an:

\frac{1}{a ^{b}} = a^{- b}

\frac{1}{e ^{- 2 x}} = e^{2 x}

= \int_{- 2}^{0} e^{2 x} d x

Wende U-Substitution an

= \int_{- 4}^{0} e^{u} \frac{1}{2} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{- 4}^{0} e^{u} d u

Nutze das gemeinsame Integral :

\int e^{u} d u = e^{u}

= \frac{1}{2} [e^{u}]_{- 4}^{0}

Berechne die Grenzen:

1 - \frac{1}{e ^{4}}

= \frac{1}{2} (1 - \frac{1}{e ^{4}})

Vereinfache

= \frac{e ^{4} - 1}{2 e ^{4}}

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