integral from 0 to pi of 2x

Lösung

\int_{0}^{π} 2 x d x

π^{2}

Dezimale

9.86960 \dots

Schritte zur Lösung

\int_{0}^{π} 2 x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{π} x d x

Wende die Potenzregel an

= 2 [\frac{x ^{2}}{2}]_{0}^{π}

Berechne die Grenzen:

\frac{π ^{2}}{2}

= 2 \cdot \frac{π ^{2}}{2}

Vereinfache

= π^{2}

\int_{1}^{2} x^{2} cos (2 x) d x

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\int_{2}^{4} arcsec (x) d x

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\int_{0}^{\infty} e^{- 66 x} x d x