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人気のある微分積分 >

integral from pi/4 to pi/3 of tan(x)

解

\int_{\frac{π}{4}}^{\frac{π}{3}} tan (x) d x

解

\frac{1}{2} ln (2)

+1

十進法表記

0.34657 \dots

解答ステップ

\int_{\frac{π}{4}}^{\frac{π}{3}} tan (x) d x

三角関数の公式を使用して書き換える

= \int_{\frac{π}{4}}^{\frac{π}{3}} \frac{sin ( x )}{cos ( x )} d x

u置換積分法を適用する

= \int_{\frac{2}{2}}^{\frac{1}{2}} - \frac{1}{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{\frac{1}{2}}^{\frac{2}{2}} - \frac{1}{u} d u

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{\frac{1}{2}}^{\frac{2}{2}} \frac{1}{u} d u)

共通積分を使用する:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - (- [ln ∣ u ∣]_{\frac{1}{2}}^{\frac{2}{2}})

簡素化

- (- [ln ∣ u ∣]_{\frac{1}{2}}^{\frac{2}{2}}) : [ln ∣ u ∣]_{\frac{1}{2}}^{\frac{1}{2}}

= [ln ∣ u ∣]_{\frac{1}{2}}^{\frac{1}{2}}

限度を計算する:

\frac{1}{2} ln (2)

= \frac{1}{2} ln (2)

グラフ

人気の例

integral from 0 to x^4 of cos^2(θ)

\int_{0}^{x^{4}} cos^{2} (θ) d θ

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\int_{7}^{9} (x^{2} + 2 x - 6) d x

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\int_{0}^{1} (2 a + 1)^{4} d a

integral from 0 to 1 of f(t)

\int_{0}^{1} f (t) d t

integral from 1 to 6 of 3/x

\int_{1}^{6} \frac{3}{x} d x