integral from 0 to sin(y) of (1+cos(y))

Lösung

\int_{0}^{s i n (y)} (1 + cos (y)) d y

sin (y) + sin (sin (y))

Schritte zur Lösung

\int_{0}^{s i n (y)} 1 + cos (y) d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{s i n (y)} 1 d y + \int_{0}^{s i n (y)} cos (y) d y

\int_{0}^{s i n (y)} 1 d y = sin (y)

\int_{0}^{s i n (y)} cos (y) d y = sin (sin (y))

= sin (y) + sin (sin (y))

\int_{- 2}^{3} \frac{1}{x ^{3}} d x

\int_{0}^{6} 16 - 2 x d x

\int_{- 1}^{1} (1 + x + x^{2} + x^{3}) d x

\int_{0}^{x} x^{2} e^{x y} d y

\int_{3}^{5} 3 x (x + 2) d x