integral from 1 to 4 of 1/((x+1)^2)

Lösung

\int_{1}^{4} \frac{1}{( x + 1 ) ^{2}} d x

\frac{3}{10}

Dezimale

0.3

Schritte zur Lösung

\int_{1}^{4} \frac{1}{( x + 1 ) ^{2}} d x

Wende U-Substitution an

= \int_{2}^{5} \frac{1}{u ^{2}} d u

Wende die Potenzregel an

= [- \frac{1}{u}]_{2}^{5}

Berechne die Grenzen:

\frac{3}{10}

= \frac{3}{10}

\int_{0}^{4} ln (x) d x

\int_{0}^{1 - x} 2 d y

\int_{0}^{1} \frac{1}{( 1 + x ^{2} )} d x

\int_{0}^{8} \frac{1}{x ^{2} + 64} d x

\int_{0}^{t} e^{- t} d t