integral from 2 to 5 of (3x+1)

Lösung

\int_{2}^{5} (3 x + 1) d x

\frac{69}{2}

Dezimale

34.5

Schritte zur Lösung

\int_{2}^{5} 3 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{5} 3 x d x + \int_{2}^{5} 1 d x

\int_{2}^{5} 3 x d x = \frac{63}{2}

\int_{2}^{5} 1 d x = 3

= \frac{63}{2} + 3

Vereinfache

\frac{63}{2} + 3 : \frac{69}{2}

= \frac{69}{2}

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