What is the integral of-1/u ?

The integral of-1/u is -ln|u|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-1/u

\int - \frac{1}{u} d u

- ln ∣ u ∣ + C

Solution steps

\int - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - ln ∣ u ∣

Add a constant to the solution

= - ln ∣ u ∣ + C

\int \frac{( x + 4 ) ( x - 7 )}{x ^{2}} d x

\frac{\partial}{\partial x} (\frac{x + 5}{y + 4})

\int \frac{1}{9 x ^{2} + 1} d x

\int sin (d) x d x

\frac{d}{d x} (\frac{x ^{3} + 1}{x ^{3} - 1})