What is the solution for y(dy)/(dx)=(y^2-y)(2x+5) ?

The solution for y(dy)/(dx)=(y^2-y)(2x+5) is y=e^{x^2+5x+c_{1}}+1

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y(dy)/(dx)=(y^2-y)(2x+5)

y \frac{d y}{d x} = (y^{2} - y) (2 x + 5)

y = e^{x^{2} + 5 x + c_{1}} + 1

Solution steps

y \frac{d y}{d x} = (y^{2} - y) (2 x + 5)

Solve separable ODE:

y = e^{x^{2} + 5 x + c_{1}} + 1

y = e^{x^{2} + 5 x + c_{1}} + 1

a^{2} - y^{2}

(x^{2} + 9) y^{^{'}} + x y = 0

\frac{d}{d y} (x cos (y))

\int \frac{x ^{3} + x ^{2}}{x ^{2} + 5 x + 6} d x

\frac{d}{d x} (\frac{x ^{2} e ^{x}}{x ^{2} + e ^{x}})

What is the solution for y(dy)/(dx)=(y^2-y)(2x+5) ?
The solution for y(dy)/(dx)=(y^2-y)(2x+5) is y=e^{x^2+5x+c_{1}}+1