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人気のある微分積分 >

derivative acos^2(x)+bx

解

導関数

a cos^{2} (x) + b x

解

- a sin (2 x) + b

解答ステップ

\frac{d}{d x} (a cos^{2} (x) + b x)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a cos^{2} (x)) + \frac{d}{d x} (b x)

\frac{d}{d x} (a cos^{2} (x)) = - a sin (2 x)

\frac{d}{d x} (b x) = b

= - a sin (2 x) + b

グラフ

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