What is the solution for y^{''}-8y^'-17y=0 ?

The solution for y^{''}-8y^'-17y=0 is y=c_{1}e^{(4+sqrt(33))t}+c_{2}e^{(4-sqrt(33))t}

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y^{''}-8y^'-17y=0

y^{^{''}} - 8 y^{^{'}} - 17 y = 0

y = c_{1} e^{(4 + 33) t} + c_{2} e^{(4 - 33) t}

Solution steps

y^{''} (t) - 8 y^{'} (t) - 17 y = 0

Solve linear ODE:

y = c_{1} e^{(4 + 33) t} + c_{2} e^{(4 - 33) t}

y = c_{1} e^{(4 + 33) t} + c_{2} e^{(4 - 33) t}

\frac{d}{d x} (3 x^{2} y - 2 x^{2} y^{2} + 3 y)

\int_{0}^{\frac{π}{4}} 2 tan^{5} (x) d x

x^{2} - 2 x + 42

\frac{1}{7} x, 7 x^{2}

x \to \infty lim ((x^{2} - 1) e^{- x^{2}})

What is the solution for y^{''}-8y^'-17y=0 ?
The solution for y^{''}-8y^'-17y=0 is y=c_{1}e^{(4+sqrt(33))t}+c_{2}e^{(4-sqrt(33))t}