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Popular >

y^'+10y=1

Solution

y^{^{'}} + 10 y = 1

Solution

y = - \frac{e ^{- 10 t - c_{1}}}{10} + \frac{1}{10}

Solution steps

y^{'} (t) + 10 y = 1

Solve separable ODE:

y = - \frac{e ^{- 10 t - c_{1}}}{10} + \frac{1}{10}

y = - \frac{e ^{- 10 t - c_{1}}}{10} + \frac{1}{10}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+10y=1 ?
The solution for y^'+10y=1 is y=-(e^{-10t-c_{1}})/(10)+1/10