y^'+10y=1

Lösung

y^{^{'}} + 10 y = 1

y = - \frac{e ^{- 10 t - c_{1}}}{10} + \frac{1}{10}

Schritte zur Lösung

y^{'} (t) + 10 y = 1

Solve separable ODE:

y = - \frac{e ^{- 10 t - c_{1}}}{10} + \frac{1}{10}

y = - \frac{e ^{- 10 t - c_{1}}}{10} + \frac{1}{10}

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