What is the derivative of f(x)= 3/((x+1)^2) ?

The derivative of f(x)= 3/((x+1)^2) is -6/((x+1)^3)

What is the first derivative of f(x)= 3/((x+1)^2) ?

The first derivative of f(x)= 3/((x+1)^2) is -6/((x+1)^3)

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derivative of

f (x) = \frac{3}{( x + 1 ) ^{2}}

- \frac{6}{( x + 1 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{3}{( x + 1 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{( x + 1 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((x + 1)^{- 2})

Apply the chain rule:

- \frac{2}{( x + 1 ) ^{3}} \frac{d}{d x} (x + 1)

= - \frac{2}{( x + 1 ) ^{3}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 3 (- \frac{2}{( x + 1 ) ^{3}} \cdot 1)

Simplify

3 (- \frac{2}{( x + 1 ) ^{3}} \cdot 1) : - \frac{6}{( x + 1 ) ^{3}}

= - \frac{6}{( x + 1 ) ^{3}}

e^{- 5 x^{4}}

\frac{d}{d x} (2^{arcsech (x)})

\int \frac{x}{x ^{4} + 3} d x

\frac{12 s + 8}{( s - 1 ) ^{5}}

\frac{3}{x ^{3}} - \frac{1}{x ^{4}}

What is the derivative of f(x)= 3/((x+1)^2) ?
The derivative of f(x)= 3/((x+1)^2) is -6/((x+1)^3)
What is the first derivative of f(x)= 3/((x+1)^2) ?
The first derivative of f(x)= 3/((x+1)^2) is -6/((x+1)^3)