What is the tangent of f(x)= 1/(x-1),\at x=4 ?

The tangent of f(x)= 1/(x-1),\at x=4 is y=-1/9 x+7/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 1/(x-1),\at x=4

tangent of

f (x) = \frac{1}{x - 1}, at x = 4

y = - \frac{1}{9} x + \frac{7}{9}

Solution steps

Find the tangent point:

(4, \frac{1}{3})

Find the slope of

f (x) = \frac{1}{x - 1} : \frac{df ( x )}{d x} = - \frac{1}{( x - 1 ) ^{2}}

Compute the slope of

f (x) = \frac{1}{x - 1}

x = 4 : m = - \frac{1}{9}

Find the line with slope m=

- \frac{1}{9}

and passing through

(4, \frac{1}{3}) : y = - \frac{1}{9} x + \frac{7}{9}

y = - \frac{1}{9} x + \frac{7}{9}

\int 4 x sin (2 x^{2}) d x

\frac{\partial}{\partial x} (x^{6} + 8 x y^{5})

\frac{\partial}{\partial x} (3 x + 4 y)

(25 t) (\frac{t ^{2}}{25})

y = (x^{2} + sin (x))^{3}

What is the tangent of f(x)= 1/(x-1),\at x=4 ?
The tangent of f(x)= 1/(x-1),\at x=4 is y=-1/9 x+7/9