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Popular >

f^'(x)=sqrt(2-4)

Solution

f^{^{'}} (x) = 2 - 4

Solution

f (x) = 2 i x + c_{1}

Solution steps

f^{'} (x) = 2 - 4

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int 2 - 4 d x

\int 2 - 4 d x = 2 i x + c_{1}

f (x) = 2 i x + c_{1}

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\frac{d}{d x} (8 x^{\frac{1}{2}})

derivative of 15e^{1/x}

\frac{d}{d x} (15 e^{\frac{1}{x}})

Frequently Asked Questions (FAQ)

What is the solution for f^'(x)=sqrt(2-4) ?
The solution for f^'(x)=sqrt(2-4) is f(x)=sqrt(2)ix+c_{1}