integral of (2x^2+3x)/(x^2+1)

Lösung

\int \frac{2 x ^{2} + 3 x}{x ^{2} + 1} d x

2 (- arctan (x) + x) + \frac{3}{2} ln x^{2} + 1 + C

Schritte zur Lösung

\int \frac{2 x ^{2} + 3 x}{x ^{2} + 1} d x

Multipliziere aus

\frac{2 x ^{2} + 3 x}{x ^{2} + 1} : \frac{2 x ^{2}}{x ^{2} + 1} + \frac{3 x}{x ^{2} + 1}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2 x ^{2}}{x ^{2} + 1} d x + \int \frac{3 x}{x ^{2} + 1} d x

\int \frac{2 x ^{2}}{x ^{2} + 1} d x = 2 (- arctan (x) + x)

\int \frac{3 x}{x ^{2} + 1} d x = \frac{3}{2} ln x^{2} + 1

= 2 (- arctan (x) + x) + \frac{3}{2} ln x^{2} + 1

Füge eine Konstante zur Lösung hinzu

= 2 (- arctan (x) + x) + \frac{3}{2} ln x^{2} + 1 + C

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