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人気のある微分積分 >

integral of sqrt((sin(x))/(cos(x)))

解

\int \frac{sin ( x )}{cos ( x )} d x

解

22 (- \frac{1}{8} (ln 2 tan (x) + 22 tan (x) + 2 - 2 arctan (2 tan (x) + 1)) + \frac{1}{8} (ln 2 tan (x) - 22 tan (x) + 2 + 2 arctan (2 tan (x) - 1))) + C

解答ステップ

\int \frac{sin ( x )}{cos ( x )} d x

基本的な三角関数の公式を使用する:

\frac{sin ( x )}{cos ( x )} = tan (x)

= \int tan (x) d x

三角関数による置換を適用する

= \int \frac{u}{1 + u ^{2}} d u

置換積分法を適用する

= \int \frac{2 v}{4 + v ^{2}} d v

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{v}{4 + v ^{2}} d v

u置換積分法を適用する

= 2 \cdot \int \frac{2 w ^{2}}{4 + w ^{4}} d w

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot 2 \cdot \int \frac{w ^{2}}{4 + w ^{4}} d w

以下の部分分数を得る:

\frac{w ^{2}}{4 + w ^{4}} : - \frac{w}{4 ( w ^{2} + 2 w + 2 )} + \frac{w}{4 ( w ^{2} - 2 w + 2 )}

= 2 \cdot 2 \cdot \int - \frac{w}{4 ( w ^{2} + 2 w + 2 )} + \frac{w}{4 ( w ^{2} - 2 w + 2 )} d w

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 \cdot 2 (- \int \frac{w}{4 ( w ^{2} + 2 w + 2 )} d w + \int \frac{w}{4 ( w ^{2} - 2 w + 2 )} d w)

\int \frac{w}{4 ( w ^{2} + 2 w + 2 )} d w = \frac{1}{8} (ln w^{2} + 2 w + 2 - 2 arctan (w + 1))

\int \frac{w}{4 ( w ^{2} - 2 w + 2 )} d w = \frac{1}{8} (ln w^{2} - 2 w + 2 + 2 arctan (w - 1))

= 2 \cdot 2 (- \frac{1}{8} (ln w^{2} + 2 w + 2 - 2 arctan (w + 1)) + \frac{1}{8} (ln w^{2} - 2 w + 2 + 2 arctan (w - 1)))

代用を戻す

= 2 \cdot 2 (- \frac{1}{8} (ln (2 tan (x))^{2} + 2 2 tan (x) + 2 - 2 arctan (2 tan (x) + 1)) + \frac{1}{8} (ln (2 tan (x))^{2} - 2 2 tan (x) + 2 + 2 arctan (2 tan (x) - 1)))

簡素化

2 \cdot 2 (- \frac{1}{8} (ln (2 tan (x))^{2} + 2 2 tan (x) + 2 - 2 arctan (2 tan (x) + 1)) + \frac{1}{8} (ln (2 tan (x))^{2} - 2 2 tan (x) + 2 + 2 arctan (2 tan (x) - 1))) : 22 (- \frac{1}{8} (ln 2 tan (x) + 22 tan (x) + 2 - 2 arctan (2 tan (x) + 1)) + \frac{1}{8} (ln 2 tan (x) - 22 tan (x) + 2 + 2 arctan (2 tan (x) - 1)))

= 22 (- \frac{1}{8} (ln 2 tan (x) + 22 tan (x) + 2 - 2 arctan (2 tan (x) + 1)) + \frac{1}{8} (ln 2 tan (x) - 22 tan (x) + 2 + 2 arctan (2 tan (x) - 1)))

定数を解答に追加する

= 22 (- \frac{1}{8} (ln 2 tan (x) + 22 tan (x) + 2 - 2 arctan (2 tan (x) + 1)) + \frac{1}{8} (ln 2 tan (x) - 22 tan (x) + 2 + 2 arctan (2 tan (x) - 1))) + C

グラフ

人気の例

integral of (xsqrt(8-x^2))

\int (x 8 - x^{2}) d x

integral of (2x+3)/(x^2+4x+10)

\int \frac{2 x + 3}{x ^{2} + 4 x + 10} d x

integral of pi(sec^2(x))(tan(x)+4)^4

\int π (sec^{2} (x)) (tan (x) + 4)^{4} d x

integral of e^xcos(0.5x)

\int e^{x} cos (0.5 x) d x

integral of (x^p)/(p+1)

\int \frac{x ^{p}}{p + 1} d x