What is the integral from 0 to pi/4 of 6sec^2(x) ?

The integral from 0 to pi/4 of 6sec^2(x) is 6

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integral from 0 to pi/4 of 6sec^2(x)

\int_{0}^{\frac{π}{4}} 6 sec^{2} (x) d x

6

Solution steps

\int_{0}^{\frac{π}{4}} 6 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{0}^{\frac{π}{4}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 6 [tan (x)]_{0}^{\frac{π}{4}}

Compute the boundaries:

1

= 6 \cdot 1

Simplify

= 6

\int \frac{y ^{5} - 1}{y} d y

\frac{d}{d x} (1 + 3^{s i n (x^{3})})

(x^{3} + 2 x + 6) (4 + \frac{1}{x ^{2}})

\int x^{2} csc (x^{3}) cot (x^{3}) d x

f (x) = - 4 x^{2} - 3 x

What is the integral from 0 to pi/4 of 6sec^2(x) ?
The integral from 0 to pi/4 of 6sec^2(x) is 6