What is the tangent of 3sqrt(x),\at x=4 ?

The tangent of 3sqrt(x),\at x=4 is y= 3/4 x+3

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tangent of 3sqrt(x),\at x=4

tangent of

3 x, at x = 4

y = \frac{3}{4} x + 3

Solution steps

Find the tangent point:

(4, 6)

Find the slope of

y = 3 x : \frac{d y}{d x} = \frac{3}{2 x}

Compute the slope of

y = 3 x

x = 4 : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(4, 6) : y = \frac{3}{4} x + 3

y = \frac{3}{4} x + 3

\int 5 tan^{3} (x) sec^{3} (x) d x

\int_{1}^{4} \frac{1}{x} d x

\frac{\partial}{\partial x} (arcsin (x yz))

\int \frac{x ^{3}}{( 5 - x ^{4} ) ^{6}} d x

\frac{d y}{d x} = - x y

What is the tangent of 3sqrt(x),\at x=4 ?
The tangent of 3sqrt(x),\at x=4 is y= 3/4 x+3