What is the solution for (dy)/(dx)-xe^y=2e^y ?

The solution for (dy)/(dx)-xe^y=2e^y is y=-ln(-2x-(x^2)/2-c_{1})

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(dy)/(dx)-xe^y=2e^y

\frac{d y}{d x} - x e^{y} = 2 e^{y}

y = - ln (- 2 x - \frac{x ^{2}}{2} - c_{1})

Solution steps

\frac{d y}{d x} - x e^{y} = 2 e^{y}

Solve separable ODE:

y = - ln (- 2 x - \frac{x ^{2}}{2} - c_{1})

y = - ln (- 2 x - \frac{x ^{2}}{2} - c_{1})

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + y = e^{- x} \cdot ln (x)

\frac{\partial}{\partial x} (1 + x y^{2})

h \to 0 lim (\frac{3}{h})

4 tan^{2} (7 x)

\frac{d y}{d x} = - \frac{1}{2} y

What is the solution for (dy)/(dx)-xe^y=2e^y ?
The solution for (dy)/(dx)-xe^y=2e^y is y=-ln(-2x-(x^2)/2-c_{1})