해법
∫(x+sin(x))3(1+cos(x))dx
해법
4x4+x3sin(x)−43x2cos(2x)+23x2−43x2+xsin3(x)−31cos3(x)+31cos3(x)+41sin4(x)+C
솔루션 단계
∫(x+sin(x))3(1+cos(x))dx
(x+sin(x))3(1+cos(x))확대한다:x3+x3cos(x)+3x2sin(x)+3x2sin(x)cos(x)+3xsin2(x)+3xsin2(x)cos(x)+sin3(x)+sin3(x)cos(x)
=∫x3+x3cos(x)+3x2sin(x)+3x2sin(x)cos(x)+3xsin2(x)+3xsin2(x)cos(x)+sin3(x)+sin3(x)cos(x)dx
합계 규칙 적용: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx=∫x3dx+∫x3cos(x)dx+∫3x2sin(x)dx+∫3x2sin(x)cos(x)dx+∫3xsin2(x)dx+∫3xsin2(x)cos(x)dx+∫sin3(x)dx+∫sin3(x)cos(x)dx
∫x3dx=4x4
∫x3cos(x)dx=x3sin(x)−3(−x2cos(x)+2(xsin(x)+cos(x)))
∫3x2sin(x)dx=3(−x2cos(x)+2(xsin(x)+cos(x)))
∫3x2sin(x)cos(x)dx=23(−21x2cos(2x)+41(2xsin(2x)+cos(2x)))
∫3xsin2(x)dx=3(21x(x−21sin(2x))−21(2x2+41cos(2x)))
∫3xsin2(x)cos(x)dx=xsin3(x)+cos(x)−31cos3(x)
∫sin3(x)dx=−cos(x)+3cos3(x)
∫sin3(x)cos(x)dx=4sin4(x)
=4x4+x3sin(x)−3(−x2cos(x)+2(xsin(x)+cos(x)))+3(−x2cos(x)+2(xsin(x)+cos(x)))+23(−21x2cos(2x)+41(2xsin(2x)+cos(2x)))+3(21x(x−21sin(2x))−21(2x2+41cos(2x)))+xsin3(x)+cos(x)−31cos3(x)−cos(x)+3cos3(x)+4sin4(x)
4x4+x3sin(x)−3(−x2cos(x)+2(xsin(x)+cos(x)))+3(−x2cos(x)+2(xsin(x)+cos(x)))+23(−21x2cos(2x)+41(2xsin(2x)+cos(2x)))+3(21x(x−21sin(2x))−21(2x2+41cos(2x)))+xsin3(x)+cos(x)−31cos3(x)−cos(x)+3cos3(x)+4sin4(x)간소화하다 :4x4+x3sin(x)−43x2cos(2x)+23x2−43x2+xsin3(x)−31cos3(x)+31cos3(x)+41sin4(x)
=4x4+x3sin(x)−43x2cos(2x)+23x2−43x2+xsin3(x)−31cos3(x)+31cos3(x)+41sin4(x)
솔루션에 상수 추가=4x4+x3sin(x)−43x2cos(2x)+23x2−43x2+xsin3(x)−31cos3(x)+31cos3(x)+41sin4(x)+C