integral of (x^2+x+7)sqrt(x+3)

解

\int (x^{2} + x + 7) x + 3 d x

\frac{2}{7} (x + 3)^{\frac{7}{2}} - 2 (x + 3)^{\frac{5}{2}} + \frac{26}{3} (x + 3)^{\frac{3}{2}} + C

解答ステップ

\int (x^{2} + x + 7) x + 3 d x

拡張

(x^{2} + x + 7) x + 3 : x^{2} x + 3 + x x + 3 + 7 x + 3

= \int x^{2} x + 3 + x x + 3 + 7 x + 3 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} x + 3 d x + \int x x + 3 d x + \int 7 x + 3 d x

\int x^{2} x + 3 d x = \frac{2}{7} (x + 3)^{\frac{7}{2}} - \frac{12}{5} (x + 3)^{\frac{5}{2}} + 6 (x + 3)^{\frac{3}{2}}

\int x x + 3 d x = \frac{2}{5} (x + 3)^{\frac{5}{2}} - 2 (x + 3)^{\frac{3}{2}}

\int 7 x + 3 d x = \frac{14}{3} (x + 3)^{\frac{3}{2}}

= \frac{2}{7} (x + 3)^{\frac{7}{2}} - \frac{12}{5} (x + 3)^{\frac{5}{2}} + 6 (x + 3)^{\frac{3}{2}} + \frac{2}{5} (x + 3)^{\frac{5}{2}} - 2 (x + 3)^{\frac{3}{2}} + \frac{14}{3} (x + 3)^{\frac{3}{2}}

簡素化

\frac{2}{7} (x + 3)^{\frac{7}{2}} - \frac{12}{5} (x + 3)^{\frac{5}{2}} + 6 (x + 3)^{\frac{3}{2}} + \frac{2}{5} (x + 3)^{\frac{5}{2}} - 2 (x + 3)^{\frac{3}{2}} + \frac{14}{3} (x + 3)^{\frac{3}{2}} : \frac{2}{7} (x + 3)^{\frac{7}{2}} - 2 (x + 3)^{\frac{5}{2}} + \frac{26}{3} (x + 3)^{\frac{3}{2}}

= \frac{2}{7} (x + 3)^{\frac{7}{2}} - 2 (x + 3)^{\frac{5}{2}} + \frac{26}{3} (x + 3)^{\frac{3}{2}}

定数を解答に追加する

= \frac{2}{7} (x + 3)^{\frac{7}{2}} - 2 (x + 3)^{\frac{5}{2}} + \frac{26}{3} (x + 3)^{\frac{3}{2}} + C