What is the derivative of a^2+bx+c ?

The derivative of a^2+bx+c is b

What is the first derivative of a^2+bx+c ?

The first derivative of a^2+bx+c is b

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\frac{d}{d x} (a^{2} + b x + c)

b

Solution steps

\frac{d}{d x} (a^{2} + b x + c)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a^{2}) + \frac{d}{d x} (b x) + \frac{d c}{d x}

\frac{d}{d x} (a^{2}) = 0

\frac{d}{d x} (b x) = b

\frac{d c}{d x} = 0

= 0 + b + 0

Simplify

= b

\frac{d}{d x} (\frac{2 x + 3}{x + 4})

x \to 4 lim (\frac{x - 4}{x - 4})

y = 5 x + 6

\frac{d}{d x} (\frac{e ^{x} + e ^{- x}}{3})

\frac{d}{d x} (\frac{∣ x - 1 ∣}{∣ x - 3 ∣})

What is the derivative of a^2+bx+c ?
The derivative of a^2+bx+c is b
What is the first derivative of a^2+bx+c ?
The first derivative of a^2+bx+c is b