What is the tangent of y=1.1x+e^x,(0,1) ?

The tangent of y=1.1x+e^x,(0,1) is y=2.1x+1

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tangent of y=1.1x+e^x,(0,1)

tangent of

y = 1.1 x + e^{x}, (0, 1)

y = 2.1 x + 1

Solution steps

Find the slope of

y = 1.1 x + e^{x} : \frac{d y}{d x} = 1.1 + e^{x}

Compute the slope of

y = 1.1 x + e^{x}

(0, 1) : m = 2.1

Find the line with slope m=

2.1

and passing through

(0, 1) : y = 2.1 x + 1

y = 2.1 x + 1

y = 0, y = x^{2}, y = 4 x - x^{2}, [0, 2]

(1 + cos (t)) y^{^{'}} = (1 + e^{- y}) sin (t), y (0) = 0

(x^{2} + 5) (8 - x)

\int \frac{2 x}{1 + 4 x ^{2}} d x

\frac{6}{x ^{3}}

What is the tangent of y=1.1x+e^x,(0,1) ?
The tangent of y=1.1x+e^x,(0,1) is y=2.1x+1