What is the solution for (dy)/(dx)=e^{-(x+y)} ?

The solution for (dy)/(dx)=e^{-(x+y)} is y=ln(-e^{-x}+c_{1})

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(dy)/(dx)=e^{-(x+y)}

\frac{d y}{d x} = e^{- (x + y)}

y = ln (- e^{- x} + c_{1})

Solution steps

\frac{d y}{d x} = e^{- (x + y)}

Solve separable ODE:

y = ln (- e^{- x} + c_{1})

y = ln (- e^{- x} + c_{1})

\int e^{- x + 2} d x

y = 4 (x + 1), y = 5 (x + 1), x = 5

f (x) = 9 sin (x) cos (x)

\int sin (x) cos (2 x) d x

cos (x^{3})

What is the solution for (dy)/(dx)=e^{-(x+y)} ?
The solution for (dy)/(dx)=e^{-(x+y)} is y=ln(-e^{-x}+c_{1})