What is the derivative of-(10/(10-x)) ?

The derivative of-(10/(10-x)) is -(10)/((10-x)^2)

What is the first derivative of-(10/(10-x)) ?

The first derivative of-(10/(10-x)) is -(10)/((10-x)^2)

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\frac{d}{d x} (- \frac{10}{10 - x})

- \frac{10}{( 10 - x ) ^{2}}

Solution steps

\frac{d}{d x} (- \frac{10}{10 - x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 10 \frac{d}{d x} (\frac{1}{10 - x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 10 \frac{d}{d x} ((10 - x)^{- 1})

Apply the chain rule:

- \frac{1}{( 10 - x ) ^{2}} \frac{d}{d x} (10 - x)

= - \frac{1}{( 10 - x ) ^{2}} \frac{d}{d x} (10 - x)

\frac{d}{d x} (10 - x) = - 1

= - 10 (- \frac{1}{( 10 - x ) ^{2}} (- 1))

Simplify

- 10 (- \frac{1}{( 10 - x ) ^{2}} (- 1)) : - \frac{10}{( 10 - x ) ^{2}}

= - \frac{10}{( 10 - x ) ^{2}}

\int \frac{1}{x \cdot 1 - x ^{2}} d x

\frac{d}{d x} (a x e^{2 x})

f (x) = x^{3} + x^{2} + (\frac{6}{x}), at x = 1

y = (x - 4)^{2}, at x = 5

\frac{d y}{d t} = - 2 y + 10

What is the derivative of-(10/(10-x)) ?
The derivative of-(10/(10-x)) is -(10)/((10-x)^2)
What is the first derivative of-(10/(10-x)) ?
The first derivative of-(10/(10-x)) is -(10)/((10-x)^2)