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Popular >

y^'+2/x y=y^2,y(1)=3

Solution

y^{^{'}} + \frac{2}{x} y = y^{2}, y (1) = 3

Solution

y = \frac{3}{x ( 3 - 2 x )}

Solution steps

y^{'} (x) + \frac{2}{x} y = y^{2}

Solve Bernoulli ODE:

y = \frac{3}{x ( 3 - 2 x )}

y = \frac{3}{x ( 3 - 2 x )}

Popular Examples

derivative of a/(2y)

\frac{d}{d x} (\frac{a}{2 y})

t^{3} y^{^{'}} + 4 t^{2} y = 0

integral of (3sin^3(x))/(cos(x))

\int \frac{3 sin ^{3} ( x )}{cos ( x )} d x

(\partial)/(\partial x)(2x^2+3y^2+z^2)

\frac{\partial}{\partial x} (2 x^{2} + 3 y^{2} + z^{2})

derivative of (2x+1/(x-3))

\frac{d}{d x} (\frac{2 x + 1}{x - 3})

Frequently Asked Questions (FAQ)

What is the solution for y^'+2/x y=y^2,y(1)=3 ?
The solution for y^'+2/x y=y^2,y(1)=3 is y= 3/(x(3-2x))