What is the slope of f(x)=x^2+x-3 ?

The slope of f(x)=x^2+x-3 is 2x+1

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slope of f(x)=x^2+x-3

slope

f (x) = x^{2} + x - 3

2 x + 1

Solution steps

f (x) = x^{2} + x - 3

In order to find the slope of the function, take the derivative of

x^{2} + x - 3

\frac{d}{d x} (x^{2} + x - 3) = 2 x + 1

2 x + 1

3 t^{4} y^{^{''}} + 7 t^{3} y^{^{'}} = 0

n = 0 \sum \infty \frac{1}{( n + 10 )}

\int 14 tan^{3} (x) d x

y^{^{''}} - 2 y + y = 0

\int_{- 4}^{6} f (x) d x