integral of (x^2+1)*sin(2x)

Lösung

\int (x^{2} + 1) \cdot sin (2 x) d x

- \frac{1}{2} x^{2} cos (2 x) + \frac{1}{2} x sin (2 x) - \frac{1}{4} cos (2 x) + C

Schritte zur Lösung

\int (x^{2} + 1) sin (2 x) d x

Wende die partielle Integration an

= - \frac{1}{2} cos (2 x) (x^{2} + 1) - \int - x cos (2 x) d x

\int - x cos (2 x) d x = - \frac{1}{4} (2 x sin (2 x) + cos (2 x))

= - \frac{1}{2} cos (2 x) (x^{2} + 1) - (- \frac{1}{4} (2 x sin (2 x) + cos (2 x)))

Vereinfache

- \frac{1}{2} cos (2 x) (x^{2} + 1) - (- \frac{1}{4} (2 x sin (2 x) + cos (2 x))) : - \frac{1}{2} x^{2} cos (2 x) + \frac{1}{2} x sin (2 x) - \frac{1}{4} cos (2 x)

= - \frac{1}{2} x^{2} cos (2 x) + \frac{1}{2} x sin (2 x) - \frac{1}{4} cos (2 x)

Füge eine Konstante zur Lösung hinzu

= - \frac{1}{2} x^{2} cos (2 x) + \frac{1}{2} x sin (2 x) - \frac{1}{4} cos (2 x) + C

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