What is the derivative of 14^{2x} ?

The derivative of 14^{2x} is ln(14)*49^x*2^{2x+1}

What is the first derivative of 14^{2x} ?

The first derivative of 14^{2x} is ln(14)*49^x*2^{2x+1}

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\frac{d}{d x} (1 4^{2 x})

ln (14) \cdot 4 9^{x} \cdot 2^{2 x + 1}

Solution steps

\frac{d}{d x} (1 4^{2 x})

Simplify

1 4^{2 x} : 19 6^{x}

= \frac{d}{d x} (19 6^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 19 6^{x} ln (196)

Simplify

19 6^{x} ln (196) : ln (14) \cdot 4 9^{x} \cdot 2^{2 x + 1}

= ln (14) \cdot 4 9^{x} \cdot 2^{2 x + 1}

\frac{5 u}{4 u ^{2} + 1}

f (x) = x + 2, at x = 2

x^{3} + x^{2} + \frac{6}{x}

\int \frac{8 x}{x ^{2} - 3} d x

What is the derivative of 14^{2x} ?
The derivative of 14^{2x} is ln(14)*49^x*2^{2x+1}
What is the first derivative of 14^{2x} ?
The first derivative of 14^{2x} is ln(14)*49^x*2^{2x+1}