What is the derivative of x^2-8ln(x) ?

The derivative of x^2-8ln(x) is 2x-8/x

What is the first derivative of x^2-8ln(x) ?

The first derivative of x^2-8ln(x) is 2x-8/x

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\frac{d}{d x} (x^{2} - 8 ln (x))

2 x - \frac{8}{x}

Solution steps

\frac{d}{d x} (x^{2} - 8 ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (8 ln (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 ln (x)) = \frac{8}{x}

= 2 x - \frac{8}{x}

\int e^{x} d x

x \to 0 - lim (\frac{x ^{2}}{x})

y = (4 x - 1)^{3}

y = 7 x - x^{2}, at x = 1

f (x) = 3^{c o s (x)}

What is the derivative of x^2-8ln(x) ?
The derivative of x^2-8ln(x) is 2x-8/x
What is the first derivative of x^2-8ln(x) ?
The first derivative of x^2-8ln(x) is 2x-8/x