What is the integral of x/(25+4x^2) ?

The integral of x/(25+4x^2) is 1/8 ln|25+4x^2|+C

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integral of x/(25+4x^2)

\int \frac{x}{25 + 4 x ^{2}} d x

\frac{1}{8} ln 25 + 4 x^{2} + C

Solution steps

\int \frac{x}{25 + 4 x ^{2}} d x

Apply u-substitution

: \int \frac{1}{8 u} d u

= \int \frac{1}{8 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{8} ln ∣ u ∣

Substitute back

u = 25 + 4 x^{2}

= \frac{1}{8} ln 25 + 4 x^{2}

Add a constant to the solution

= \frac{1}{8} ln 25 + 4 x^{2} + C

\frac{d}{d t} (\frac{k}{t})

\frac{d}{d x} (e^{x y} (y + x \frac{d y}{d x}))

\int \frac{6}{x ln ( x )} d x

G (t) = \frac{1 - 6 t}{2 + t}

What is the integral of x/(25+4x^2) ?
The integral of x/(25+4x^2) is 1/8 ln|25+4x^2|+C