integral of x(x+5)^5

解

\int x (x + 5)^{5} d x

\frac{x ^{7}}{7} + \frac{25 x ^{6}}{6} + 50 x^{5} + \frac{625 x ^{4}}{2} + \frac{3125 x ^{3}}{3} + \frac{3125 x ^{2}}{2} + C

解答ステップ

\int x (x + 5)^{5} d x

拡張

x (x + 5)^{5} : x^{6} + 25 x^{5} + 250 x^{4} + 1250 x^{3} + 3125 x^{2} + 3125 x

= \int x^{6} + 25 x^{5} + 250 x^{4} + 1250 x^{3} + 3125 x^{2} + 3125 x d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{6} d x + \int 25 x^{5} d x + \int 250 x^{4} d x + \int 1250 x^{3} d x + \int 3125 x^{2} d x + \int 3125 x d x

\int x^{6} d x = \frac{x ^{7}}{7}

\int 25 x^{5} d x = \frac{25 x ^{6}}{6}

\int 250 x^{4} d x = 50 x^{5}

\int 1250 x^{3} d x = \frac{625 x ^{4}}{2}

\int 3125 x^{2} d x = \frac{3125 x ^{3}}{3}

\int 3125 x d x = \frac{3125 x ^{2}}{2}

= \frac{x ^{7}}{7} + \frac{25 x ^{6}}{6} + 50 x^{5} + \frac{625 x ^{4}}{2} + \frac{3125 x ^{3}}{3} + \frac{3125 x ^{2}}{2}

定数を解答に追加する

= \frac{x ^{7}}{7} + \frac{25 x ^{6}}{6} + 50 x^{5} + \frac{625 x ^{4}}{2} + \frac{3125 x ^{3}}{3} + \frac{3125 x ^{2}}{2} + C