What is the derivative of sin(x-e^x) ?

The derivative of sin(x-e^x) is cos(x)-e^x

What is the first derivative of sin(x-e^x) ?

The first derivative of sin(x-e^x) is cos(x)-e^x

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\frac{d}{d x} (sin (x) - e^{x})

cos (x) - e^{x}

Solution steps

\frac{d}{d x} (sin (x) - e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (x)) - \frac{d}{d x} (e^{x})

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (e^{x}) = e^{x}

= cos (x) - e^{x}

y^{^{''}} + 2 y^{^{'}} + 2 y = sin (2 t), y (0) = 0, y^{^{'}} (0) = 0

\frac{d}{d r ( d )} ([\frac{12.61}{0.45} (84.4)] r (d) a d)

\int_{- 2}^{1} (1 - 2 x) d x

\int \frac{( tan ( x ) + sin ( x ) )}{sec ( x )} d x

\int (4 + x^{6})^{6} x^{5} d x

What is the derivative of sin(x-e^x) ?
The derivative of sin(x-e^x) is cos(x)-e^x
What is the first derivative of sin(x-e^x) ?
The first derivative of sin(x-e^x) is cos(x)-e^x