What is (\partial)/(\partial x)(ln(x+sqrt(y))) ?

The answer to (\partial)/(\partial x)(ln(x+sqrt(y))) is 1/(x+sqrt(y))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(ln(x+sqrt(y)))

\frac{\partial}{\partial x} (ln (x + y))

\frac{1}{x + y}

Solution steps

\frac{\partial}{\partial x} (ln (x + y))

Treat

y

as a constant

Apply the chain rule:

\frac{1}{x + y} \frac{\partial}{\partial x} (x + y)

= \frac{1}{x + y} \frac{\partial}{\partial x} (x + y)

\frac{\partial}{\partial x} (x + y) = 1

= \frac{1}{x + y} \cdot 1

Simplify

= \frac{1}{x + y}

y^{^{'}} = e^{(y - x)}

(\frac{q ^{4}}{4} + \frac{2 q ^{3}}{3} - \frac{11 q ^{2}}{2} + 12 q)^{^{'}}

4 (1 + x^{2}) \frac{d y}{d x} = 2 x y (y^{4} - 1)

f (x) = \frac{3}{4} x

f (x) = (arctan (8 x))^{2}

What is (\partial)/(\partial x)(ln(x+sqrt(y))) ?
The answer to (\partial)/(\partial x)(ln(x+sqrt(y))) is 1/(x+sqrt(y))