sqrt(x)+sqrt(y)*y^'=0

Lösung

x + y \cdot y^{^{'}} = 0

y = 3 x^{3} - 3 c_{1} x^{\frac{3}{2}} + \frac{9 c _{1}^{2}}{4}

Schritte zur Lösung

x + y \cdot y^{'} (x) = 0

Solve separable ODE:

y = 3 x^{3} - 3 c_{1} x^{\frac{3}{2}} + \frac{9 c _{1}^{2}}{4}

y = 3 x^{3} - 3 c_{1} x^{\frac{3}{2}} + \frac{9 c _{1}^{2}}{4}

t an g e n t f (x) = (3 x - 1)^{2}, at x = 1

x \to 2 lim (x^{2} - x - 6)

\frac{\partial}{\partial x} (2 x^{3} - 10 y)

\int_{6}^{8} \frac{y}{y ^{2} - 2 y - 3} d y

\int (x^{3} - 1)^{4} x^{2} d x