What is the first derivative of 2x^2-8 ?

The first derivative of 2x^2-8 is 4x

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derivative of 2x^2-8

\frac{d}{d x} (2 x^{2} - 8)

4 x

Solution steps

\frac{d}{d x} (2 x^{2} - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (8)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (8) = 0

= 4 x - 0

Simplify

= 4 x

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