What is the derivative of 3/4 x^{4/3}-3/8 x^{2/3}+9 ?

The derivative of 3/4 x^{4/3}-3/8 x^{2/3}+9 is (-1+4x^{2/3})/(4x^{1/3)}

What is the first derivative of 3/4 x^{4/3}-3/8 x^{2/3}+9 ?

The first derivative of 3/4 x^{4/3}-3/8 x^{2/3}+9 is (-1+4x^{2/3})/(4x^{1/3)}

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\frac{d}{d x} (\frac{3}{4} x^{\frac{4}{3}} - \frac{3}{8} x^{\frac{2}{3}} + 9)

\frac{- 1 + 4 x ^{\frac{2}{3}}}{4 x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (\frac{3}{4} x^{\frac{4}{3}} - \frac{3}{8} x^{\frac{2}{3}} + 9)

Simplify

\frac{3}{4} x^{\frac{4}{3}} - \frac{3}{8} x^{\frac{2}{3}} + 9 : \frac{3 x ^{\frac{4}{3}}}{4} - \frac{3 x ^{\frac{2}{3}}}{8} + 9

= \frac{d}{d x} (\frac{3 x ^{\frac{4}{3}}}{4} - \frac{3 x ^{\frac{2}{3}}}{8} + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3 x ^{\frac{4}{3}}}{4}) - \frac{d}{d x} (\frac{3 x ^{\frac{2}{3}}}{8}) + \frac{d}{d x} (9)

\frac{d}{d x} (\frac{3 x ^{\frac{4}{3}}}{4}) = x^{\frac{1}{3}}

\frac{d}{d x} (\frac{3 x ^{\frac{2}{3}}}{8}) = \frac{1}{4 x ^{\frac{1}{3}}}

\frac{d}{d x} (9) = 0

= x^{\frac{1}{3}} - \frac{1}{4 x ^{\frac{1}{3}}} + 0

Simplify

x^{\frac{1}{3}} - \frac{1}{4 x ^{\frac{1}{3}}} + 0 : \frac{- 1 + 4 x ^{\frac{2}{3}}}{4 x ^{\frac{1}{3}}}

= \frac{- 1 + 4 x ^{\frac{2}{3}}}{4 x ^{\frac{1}{3}}}

\int \frac{( a ^{x} - b ^{x} ) ^{2}}{a ^{x} b ^{x}} d x

\frac{d y}{d x} = e^{7 x - 7 y}

\frac{\partial}{\partial z} (2 z)

y^{^{'}} + y = 1

y^{^{''}} + 4 y^{^{'}} + 4 y = 4 - t

What is the derivative of 3/4 x^{4/3}-3/8 x^{2/3}+9 ?
The derivative of 3/4 x^{4/3}-3/8 x^{2/3}+9 is (-1+4x^{2/3})/(4x^{1/3)}
What is the first derivative of 3/4 x^{4/3}-3/8 x^{2/3}+9 ?
The first derivative of 3/4 x^{4/3}-3/8 x^{2/3}+9 is (-1+4x^{2/3})/(4x^{1/3)}